121r^2=62

Solution for 121r^2=62 equation:

121r^2=62

We move all terms to the left:

121r^2-(62)=0

a = 121; b = 0; c = -62;
Δ = b2-4ac
Δ = 02-4·121·(-62)
Δ = 30008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30008}=\sqrt{484*62}=\sqrt{484}*\sqrt{62}=22\sqrt{62}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{62}}{2*121}=\frac{0-22\sqrt{62}}{242}
=-\frac{22\sqrt{62}}{242}
=-\frac{\sqrt{62}}{11}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{62}}{2*121}=\frac{0+22\sqrt{62}}{242}
=\frac{22\sqrt{62}}{242}
=\frac{\sqrt{62}}{11}
$